A bag contains five-rupee, one-rupee, 50-paise, and 25-paise coins in the ratio 3 : 5 : 6 : 8. If the total amount of money in the bag is ₹225. The number of coins of each kind in ascending order:
(A) No. of coins of 25 paise
(B) No. of coins of one rupee
(C) No. of coins of 50 paise
(D) No. of coins of five rupee
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (D), (B), (C), (A)
The ratio 3 : 5 : 6 : 8 is the ratio of the numbers of coins, not of their values. Each number is multiplied by the value of one coin, and the values together make ₹225.
Finding k (numbers of coins \(3k, 5k, 6k, 8k\)):
Value of the five-rupee coins: \(5\times3k=15k\)
Value of the one-rupee coins: \(1\times5k=5k\)
Value of the 50-paise coins: \(0.50\times6k=3k\)
Value of the 25-paise coins: \(0.25\times8k=2k\)
\(15k+5k+3k+2k=25k=225\), so \(k=9\)
Number of each kind, from the smallest:
(D) five-rupee coins: \(3\times9=27\)
(B) one-rupee coins: \(5\times9=45\)
(C) 50-paise coins: \(6\times9=54\)
(A) 25-paise coins: \(8\times9=72\)