Amines
Amines can be considered as derivatives of ammonia, obtained by replacement of one, two or all the three hydrogen atoms by alkyl and/or aryl groups. They are classified as primary (1°), secondary (2°) and tertiary (3°) depending upon the number of hydrogen atoms replaced by alkyl or aryl groups in ammonia molecule. In aryl amines, –NH2 group is directly attached to the benzene ring. C6H5NH2 is the simplest example of aryl amine. Amines can be prepared by various synthetic pathways. For example the reduction of nitro compounds with metals in acidic medium produces amines. Reduction with iron scrap and hydrochloric acid is preferred because FeCl2 formed gets hydrolyzed to release hydrochloric acid during the reaction. Thus, only a small amount of hydrochloric acid is required to initiate the reaction.
Similarly, an alkyl or benzyl halide on reaction with an ethanolic solution of ammonia undergoes nucleophilic substitution reaction in which the halogen atom is replaced by an amino (–NH2) group. The primary amine thus obtained behaves as a nucleophile and can further react with alkyl halide to form secondary and tertiary amines, and finally quaternary ammonium salt. Reduction of nitriles and amides also yield amines.
Moreover, amines behave as nucleophiles due to the presence of unshared electron pair. Amines, being basic in nature, react with acids to form salts. Basic character of amines can be better understood in terms of their Kb and pKb values. Larger the value of Kb or smaller the value of pKb, stronger is the base. Basicity of amines is related to their structure. Basic character of an amine depends upon the ease of formation of the cation by accepting a proton from the acid. The more stable the cation is relative to the amine, more basic is the amine.
Which of the following compound exhibit highest basic character in aqueous medium?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → N-Methylmethanamine
In water, the basic strength of aliphatic amines is decided by three factors acting together:
Inductive effect (+I): alkyl groups push electrons towards nitrogen and make the lone pair more available: 3° > 2° > 1°.
Solvation (hydration): the protonated amine is stabilised by hydrogen bonding with water; the more N–H hydrogens it has, the better: 1° > 2° > 3°.
Steric hindrance: bulky groups crowd the nitrogen and hinder this hydrogen bonding; least for 1°, greatest for 3°.
The balance favours the secondary amine: among the four, N-methylmethanamine, \( \ce{(CH3)2NH} \), has the smallest pKb (smaller pKb = stronger base).
So N-methylmethanamine has the smallest pKb and is the strongest base in aqueous medium.
Why the other options are incorrect
Option (1) N, N-Dimethylmethanamine — Incorrect. This tertiary amine has the strongest +I effect, but its cation has only one N–H for hydrogen bonding and is crowded, so it is the weakest base of the four in water.
Option (2) Ethanamine — Incorrect. A primary amine; it is well solvated, but its single ethyl group gives a smaller +I effect than two methyl groups.
Option (3) Methanamine — Incorrect. A primary amine with only one methyl group, so it is weaker than both \( \ce{(CH3)2NH} \) and \( \ce{C2H5NH2} \).
NCERT (2026-27 edition):
Chemical Reactions
| Name of amine | pKb |
|---|---|
| Methanamine | 3.38 |
| N-Methylmethanamine | 3.27 |
| N,N-Dimethylmethanamine | 4.22 |
| Ethanamine | 3.29 |
| N-Ethylethanamine | 3.00 |
| N,N-Diethylethanamine | 3.25 |
| Benzenamine | 9.38 |
| Phenylmethanamine | 4.70 |
| N-Methylaniline | 9.30 |
| N,N-Dimethylaniline | 8.92 |