A conducting rod of length 0.6 m moves with speed of 5 m/s horizontally in a perpendicular uniform magnetic field of 0.70 T pointing into the paper. The induced e.m.f. will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 2.10 V
A rod moving perpendicular to a magnetic field, with its length also perpendicular to the field and to its velocity, has a motional emf \( \varepsilon = Blv \).
\( \displaystyle \varepsilon = Blv = 0.70\,\mathrm{T} \times 0.6\,\mathrm{m} \times 5\,\mathrm{m\,s^{-1}} \)
\( \displaystyle \varepsilon = 2.1\,\mathrm{V} \)