Practicing Success
Practicing Success
CUET Preparation Today
If the position vector of a point A is $\vec a + 2\vec b$ and $\vec a$ divides AB in the ratio 2: 3, then the position vector of B is |
$2\vec a-\vec b$ $\vec b-2\vec a$ $\vec a-3\vec b$ $\vec b$ |
$\vec a-3\vec b$ |
Let $P (\vec a)$ divide AB in the ratio 2 : 3 and let$\vec c$ be the position vector of B. Then, $\vec a=\frac{2(\vec c)+3(\vec a +2\vec b)}{2+3}$ $⇒\vec c=\vec a-3\vec b$
|
