Practicing Success
Practicing Success
CUET Preparation Today
An LED has a voltage drop of 2 V across it and a current of 10 mA flows when it operates with a 6 V battery through a limiting resistance R. The value of R is: |
$40 k \Omega$ $4 k \Omega$ $200 \Omega$ $400 \Omega$ |
$400 \Omega$ |
The correct answer is Option (4) → $400 \Omega$ |
