Practicing Success
In the given figure, if KI = IT and EK = ET, then ∠TEI = _______. |
75° 125° 105° 150° |
105° |
Calculation In \(\Delta \)KEI and \(\Delta \)TEI ⇒ KI = IT (Given) ⇒ EK = ET (Given) ⇒ EI = EI (Common) \(\Delta \)KEI is congruent to \(\Delta \)TEI (by SSS) ⇒ \(\angle\)KEI = \(\angle\)TEI (By CPCT) Now, ⇒ \(\angle\)KET + \(\angle\)KEI + \(\angle\)TEI = \({360}^\circ\) ⇒ \({150}^\circ\) + 2 x \(\angle\)TEI = \({360}^\circ\) ⇒ 2\(\angle\)TEI = \({360}^\circ\) - \({150}^\circ\) ⇒ \(\angle\)TEI = \(\frac{210}{2}\) = \({105}^\circ\) Therefore, the answer is \({105}^\circ\) |