A circle is drawn with the hypotenuse of a right triangle as its diameter. If the other two sides of the triangle are 6 cm and 8 cm, what is the area of the circle? (Take \(\pi=\frac{22}{7}\))
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 78.57 cm2
By Pythagoras' theorem, the hypotenuse is \(\sqrt{(\text{side}_1)^2+(\text{side}_2)^2}\). The hypotenuse is the diameter, so the radius is half of it, and the area is \(\pi r^2\).
Hypotenuse \(=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10\) cm
Radius \(=10\div2=5\) cm
Area \(\displaystyle =\frac{22}{7}\times5\times5=\frac{550}{7}\approx78.57\) cm2
