Practicing Success
A volume of a wall is 128 cm3. If the height of the wall is 6 times its breadth and the length is 9 times its breadth, find the breadth. |
\(\sqrt[3]{3.45}\) cm \(\sqrt[3]{4.74}\) cm \(\sqrt[3]{2.37}\) cm \(\sqrt[3]{2.38}\) cm |
\(\sqrt[3]{2.37}\) cm |
Let the breadth = a cm Height = 6 × breadth = 6a Length = 9 × breadth = 9a Volume = Length × Breadth × Height 128 = 9a × 6a × a 128 = 54a3 a3 = \(\frac{128}{54}\) = 2.37 $⇒a=\sqrt[3]{2.37cm}$ |