Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 3D

Question:

A volume of a wall is 128 cm3. If the height of the wall is 6 times its breadth and the length is 9 times its breadth, find the breadth.

Options:

\(\sqrt[3]{3.45}\) cm

\(\sqrt[3]{4.74}\) cm

\(\sqrt[3]{2.37}\) cm

\(\sqrt[3]{2.38}\) cm

Correct Answer:

\(\sqrt[3]{2.37}\) cm

Explanation:

Let the breadth = a cm

Height = 6 × breadth = 6a

Length = 9 × breadth = 9a

Volume = Length × Breadth × Height

128 = 9a × 6a × a

128 = 54a3

a3 = \(\frac{128}{54}\) = 2.37

$⇒a=\sqrt[3]{2.37cm}$