If sin θ = 4/5, find the value of sin3θ.

we know,

sin3θ = 3sinθ - 4sin³θ 

Given:-

sinθ  = \(\frac{4}{5}\)

sin3θ = 3 ×  \(\frac{4}{5}\) - 4 × (\(\frac{4}{5}\))³

= \(\frac{12}{5}\) - \(\frac{256}{125}\)

= \(\frac{300 - 256}{125}\)

= \(\frac{44}{125}\)