The Brewster's angle for glass of refractive index 1.5 is

The correct answer is Option (1) → \( 56.3^\circ \)

At the Brewster angle \( i_B \) the reflected light is completely plane polarised, and the reflected and refracted rays are at \( 90^\circ \) to each other. This gives Brewster's law:

    \( \displaystyle \tan i_B = \mu \)

    \( \displaystyle i_B = \tan^{-1}(1.5) = 56.3^\circ \)

Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.

NCERT (Pre-rationalised edition, 2022-23):
Exercises – …