Two dice are thrown simultaneously. What is the probability that the sum of the two numbers is 4?

$\frac{1}{12}$

Possible outcomes when we throw a dice :- {1, 2, 3, 4, 5, 6}

When we throw a dice twice , total possible outcomes = 6 × 6 = 36

The possibility of getting sum of number 4 is (1, 3), (2, 2), and (3, 1).

Number of desired outcomes = 3

 Probability that the sum of the two numbers is 4

= \(\frac{3}{36}\)

= \(\frac{1}{12}\)