Practicing Success
Practicing Success
CUET Preparation Today
If $x^{\frac{3}{4}}+y^{\frac{3}{4}}=a^{\frac{3}{4}}$ (a is a constant) then $\frac{dy}{dx}$ is equal to : |
$\left(\frac{y}{x}\right)^{\frac{1}{4}}$ $\left(\frac{x}{y}\right)^{\frac{1}{4}}$ $-\left(\frac{y}{x}\right)^{\frac{1}{4}}$ $-\left(\frac{x}{y}\right)^{\frac{1}{4}}$ |
$-\left(\frac{y}{x}\right)^{\frac{1}{4}}$ |
