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If $\alpha$ and $\beta$ are two roots of $2 x^2+3 x+1=0$ value of $\alpha^2+\beta^2$ is: |
$\frac{1}{4}$ $\frac{3}{4}$ $\frac{5}{4}$ $\frac{7}{4}$ |
$\frac{5}{4}$ |
We have , $2 x^2+3 x+1=0$ = $2 x^2+2 x+x+1=0$ = 2x(x + 1) + 1(x + 1) = (2x + 1) (x + 1) Now, (2x + 1) = 0 x = -1/2 = alpha Also, (x + 1) = 0 x = -1 = beta So, value of $\alpha^2+\beta^2$ = (-1/2 )2 + (-1)2 = $\frac{5}{4}$ |
