How many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line?
Answer & explanation
Correct answer: option 2
I = n \(\frac{E}{r}\)
n = \(\frac{Ir}{E}\)
I = 5 A ; E = 220 V ; r = 176 \(\Omega\)
n = 4
How many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line?
Correct answer: option 2
I = n \(\frac{E}{r}\)
n = \(\frac{Ir}{E}\)
I = 5 A ; E = 220 V ; r = 176 \(\Omega\)
n = 4