CUET Preparation Today
Find the value of \(\frac{cos\;θ\; .\; sec\;θ\;. \;tan\;θ\;.\; cot\;θ}{sec^2θ \;-\; tan^2θ}\) . |
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\(\frac{cos\;θ\; .\; sec\;θ\;. \;tan\;θ\;.\; cot\;θ}{sec^2θ \;-\; tan^2θ}\) = 1 (because cosθ.secθ = 1), so tanθ.cotθ = 1 ⇒ sec2θ - tan2θ = 1 |
