The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc is :
Answer & explanation
Correct answer: option 3
\(I_2 = I_1 + MR^2\)
\(I_2 = \frac{3}{2} MR^2\)
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc is :
Correct answer: option 3
\(I_2 = I_1 + MR^2\)
\(I_2 = \frac{3}{2} MR^2\)