Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc is :

Options:

MR2

(2/5)MR2

(3/2)MR2

(5/6)MR2

Correct Answer:

(3/2)MR2

Explanation:

\(I_2 = I_1 + MR^2\)

\(I_2 = \frac{3}{2} MR^2\)