Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If a : b : c = 3 : 5 : 7, what is the value of  \(\frac{5a - 2b +3c}{3(a+b+c)}\) ?

Options:

\(\frac{16}{45}\)

 

\(\frac{26}{45}\)

\(\frac{46}{45}\)

1

Correct Answer:

\(\frac{26}{45}\)

Explanation:

a : b : c = 3 : 5 : 7

Put these values,

\(\frac{5a - 2b + 3c}{3 (a+b+c)}\) = \(\frac{5 × 3 - 2 ×5 + 3 × 7}{3 (3+5+7)}\) = \(\frac{26}{45}\)