The area bounded by $y^2=4 x$ and its latus rectum and x-axis in first quadrant is:

0 sq. units $\frac{4}{3}$ sq. units $\frac{2}{3}$ sq. units $\frac{1}{3}$ sq. units

$\frac{4}{3}$ sq. units

The correct answer is Option (2) - $\frac{4}{3}$ sq. units