During the first year, the population of a town increased by 12%. The next year, due to some contagious disease, it decreased by 8%. At the end of the second year, the population was 64,400. Find the population of the town at beginning of the first year.
Answer & explanation
Correct answer: option 3
Let the initial population be x.
Then, According to question,
92% of 112% of x = 64,400
0.92 × 1.12x = 64,400
x = \(\frac{64400}{0.92×1.12}\)
x = \(\frac{64400}{1.0304}\)
x = 62,500