If the value of x4+\(\frac{1}{{x}^{4}}\) = 2207
than what is the value of this equation decreased to single power and divided by four.
Answer & explanation
Correct answer: option 3
If x4+\(\frac{1}{{x}^{4}}\) = 2207
x2+\(\frac{1}{{x}^{2}}\) = \(\sqrt{2207+2}\) = 47 [If x4+\(\frac{1}{{x}^{4}}\) = m than x2+\(\frac{1}{{x}^{2}}\) = \(\sqrt {{m}^{}+2}=z\) and x+\(\frac{1}{x}\)=\(\sqrt{{z}^{}+2}\)]
x+\(\frac{1}{x}\) = \(\sqrt{47+2}\) = 7
x+\(\frac{1}{x}\) = 7
\(\frac{x+\frac{1}{x}}{4}\) = \(\frac{7}{4}\)