If the value of x⁴+\(\frac{1}{{x}^{4}}\) = 2207

than what is the value of this equation decreased to single power and divided by four.

\(\frac{7}{4}\)

If x⁴+\(\frac{1}{{x}^{4}}\) = 2207

x²+\(\frac{1}{{x}^{2}}\) = \(\sqrt{2207+2}\) = 47   [If x⁴+\(\frac{1}{{x}^{4}}\) = m than x²+\(\frac{1}{{x}^{2}}\) = \(\sqrt {{m}^{}+2}=z\) and x+\(\frac{1}{x}\)=\(\sqrt{{z}^{}+2}\)]

x+\(\frac{1}{x}\) = \(\sqrt{47+2}\) = 7

x+\(\frac{1}{x}\) = 7

\(\frac{x+\frac{1}{x}}{4}\) = \(\frac{7}{4}\)