If the value of x⁴+$\frac{1}{{x}^{4}}$ = 2207

than what is the value of this equation decreased to single power and divided by four.

$\frac{7}{4}$

If x⁴+$\frac{1}{{x}^{4}}$ = 2207

x²+$\frac{1}{{x}^{2}}$ = $\sqrt{2207+2}$ = 47   [If x⁴+$\frac{1}{{x}^{4}}$ = m than x²+$\frac{1}{{x}^{2}}$ = $\sqrt {{m}^{}+2}=z$ and x+$\frac{1}{x}$=$\sqrt{{z}^{}+2}$]

x+$\frac{1}{x}$ = $\sqrt{47+2}$ = 7

x+$\frac{1}{x}$ = 7

$\frac{x+\frac{1}{x}}{4}$ = $\frac{7}{4}$