If any four numbers are selected and they are multiplied, then the probability that the last digit will be \(1,3,5\) or \(7\) is

\(\frac{4}{25}\) \(\frac{16}{625}\) \(\frac{25}{16}\) \(\frac{1}{2}\)

\(\frac{16}{625}\)

Total cases \(=10\), Favourable cases \(=4\), Required probability \(=\left(\frac{4}{10}\right)^{4}\)