Twenty-two grams of CO2 at 27oC is mixed with 16 g of O2 at 37oC. The temperature of the mixture is about :
Answer & explanation
Correct answer: option 1
Let t be the temperature of mixture.
Heat gained by CO2 = Heat lost by O2
\(\Rightarrow \mu_1 C_{v_1} \Delta T_1 = \mu_2 C_{v_2} \Delta T_2\)
\(\Rightarrow \frac{22}{44} (3R) (t - 25) = \frac{16}{32} (\frac{5}{2}R) (35 - t)\)
\(\Rightarrow 3(t - 25) = \frac{5}{2}(35 - t)\)
t = 29.5oC