Practicing Success
Practicing Success
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If $\Delta=\left|\begin{array}{ccc}x^n & x^{n+2} & x^{2 n} \\ 1 & x^p & p \\ x^{n+5} & x^{p+6} & x^{2 n+5}\end{array}\right|=0$, then P is given by |
xn (n+ 1) either A or B both A and B |
both A and B |
C1 and C3 become equal for p = xn and R1 and R3 become equal for p = n + 1. Hence (4) is the correct answer. |
