Read the following passage and answer the next five questions based on it:
| Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
| Y | Zr | Nb | Mo | Te | Ru | Rh | Pd | Ag | Cd |
| La | Hf | Ta | W | Re | Os | Ir | Pt | Au | Hg |
In any transition series, as we move from left to right the \(d-\)orbitals are progressively filled and their properties vary accordingly
| Ce | Pr | Nd | Pm | Sm | Eu | Gd | Tb | Dy | Ho | Er | Tm | Yb | Lu |
| Th | Pa | U | Np | Pu | Am | Cm | Bk | Cf | Es | Fm | Md | No | Lr |
The above are the two series of f-block elements in which the chemical properties won't change much. The 5f-series elements are radioactive in nature and mostly are artificially synthesized in laboratories and thus much is not known about their chemical properties.
Identify the incorrect statement.
Answer & explanation
Correct answer: option 2
The correct answer is option (2) -Zr and Hf shares almost identical nuclear properties.
Statement-wise Evaluation
Option 1. Second ionization enthalpy of Ag is greater than second ionization enthalpy of Pd : Correct
- Ag configuration: $[\text{Kr}] \, 4d^{10} 5s^1$
- $1^{\text{st}}$ IE removes $5s^1 \rightarrow \text{Ag}^+$ becomes $4d^{10}$ (very stable)
- $2^{\text{nd}}$ IE removes an electron from filled $4d^{10}$ shell $\rightarrow$ requires very high energy
- Pd configuration: $[\text{Kr}] \, 4d^{10} 5s^0$
- Removing two electrons does not involve breaking an already formed $\text{Ag}^+$-type extra stability.
Therefore, second ionization enthalpy of $\text{Ag}$ is indeed higher than $\text{Pd}$.
So Statement 1 is true.
2. Zr and Hf share almost identical nuclear properties: Incorrect statement
- $\text{Zr}$ and $\text{Hf}$ are similar due to lanthanide contraction, which affects atomic size and chemical/physical properties.
- Nuclear properties relate to isotopes, binding energy, radioactivity, etc. — these are not identical.
- Textbooks always say chemical properties, not nuclear.
Hence this statement is factually wrong.
3. Melting point of Mn is lower than that of Cr : Correct
$\text{Mn}$ has relatively weaker metallic bonding compared to $\text{Cr}$, so its melting point is lower. This is a known irregular trend in the $3d$ series.
4. Interstitial compounds are non-stoichiometric and neither ionic nor covalent: Correct
They are metallic in character and usually non-stoichiometric. This is standard theory of transition metals.