Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

The lines \(\frac{x-1}{k}=\frac{y-4}{2}=\frac{z-5}{1}\) and \(\frac{x-2}{1}=\frac{y-3}{1}=\frac{z-4}{-k}\) are coplanar if the value of \(k\) is

Options:

\(2\)

\(-2\)

\(1\)

\(-3\)

Correct Answer:

\(-3\)

Explanation:

Recall the coplanarity condition for two lines.