CUET Preparation Today
The galvanometer G in the circuit reads zero (no deflection). If the batteries are resistance less, the value of R would be:
|
600Ω 1000Ω 24Ω 100Ω |
100Ω |
The correct answer is Option (4) → 100Ω
$R_{effective}=500+R$ [Connected in series] $V=12V$ $500×\frac{12}{500+R}+R×\frac{12}{500+R}=12$ $⇒R=100Ω$ |
