Practicing Success
If $\vec a,\vec b,\vec c$ be three vectors of magnitude $\sqrt{3},1,2$ such that $\vec a × (\vec a×\vec c)+3\vec b= 0$, if θ is the angle between $\vec a$ and $\vec c$, then $\cos^2θ$ is equal to |
$\frac{3}{4}$ $\frac{1}{2}$ $\frac{1}{4}$ none of these |
$\frac{3}{4}$ |
We have, $\vec a × (\vec a×\vec c)+3\vec b= 0$ $⇒(\vec a. \vec c) \vec a- (\vec a. \vec a) \vec c +3\vec b=\vec 0$ $⇒(2\sqrt{3}\cos θ)\vec a-3\vec c+3\vec b=\vec 0$ $⇒(2\cos θ)\vec a-\sqrt{3}\vec c+\sqrt{3}\vec b=\vec 0$ $⇒|2\cos θ\vec a-\sqrt{3}\vec c|^2=|-\sqrt{3}\vec b|^2$ $⇒4\cos^2 θ|\vec a|^2+3|\vec c|^2-4\sqrt{3}\cos θ(\vec a.\vec c)=3|\vec b|^2$ $⇒12\cos^2 θ+12-4\sqrt{3}\cos θ×\sqrt{3}×2\cos θ=3$ $⇒12\cos^2 θ+9-24\cos^2 θ=0$ $⇒12\cos^2 θ=9⇒\cos^2 θ=\frac{9}{12}=\frac{3}{4}$ |