The integrating factor of the differential equation $\cos x \frac{d y}{d x}+y \sin x=1$ is
Answer & explanation
Correct answer: option 1
$\cos x \frac{d y}{d x}+y \sin x=1$
$\Rightarrow \frac{d y}{d x}+y \tan x= \frac{1}{\cos x}$
So P(x) = tan x
So integrating factor = I.F = $e^{\int P(x) d x} = e^{\int \tan x d x}$
$=e^{\log \sec x}=\sec x$
Option: 1