If force (F), velocity (V) and time (T) are taken as fundamental units, then dimensions of mass are

[$FV^{-1}T$]

Let mass m =k$F^aV^bT^c$ where k is a dimensionless constant Writing the dimensions on both sides, we get [$ML^0T^0$] = $[MLT^{-2}]^a[M^0LT{-1}]^b[T]^c$

[$ML^0T^0$] =$[M^aL^{a+b}T^{-2a-2b+c}]$

Comparing both sides of the equation we get,

a = 1                   ....(1)
2a + b = 0            ....(2)
-2a - b + c = 0            ....(3)

Solving equation (1), (2) and (3), we get

a = 1, b = - 1, c = 1

∴ Dimension of mass = [$FV^{-1}T$]