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Evaluate $\begin{vmatrix} x & x + 1 \\ x - 1 & x \end{vmatrix}$. |
$x^2 + 1$ $2x^2 - 1$ $-1$ $1$ |
$1$ |
The correct answer is Option (4) → 1 ## We have $\begin{vmatrix} x & x + 1 \\ x - 1 & x \end{vmatrix} = x(x) - (x + 1)(x - 1)$ $= x^2 - (x^2 - 1) = x^2 - x^2 + 1 = 1$ |
