Practicing Success
Practicing Success
CUET Preparation Today
A long string with a charge of λ per unit length passes through an imaginary cube of edge a. The maximum flux of the electric field through the cube will be |
$\frac{\lambda a}{\varepsilon_0}$ $\frac{\sqrt{2} \lambda a}{\varepsilon_{0}}$ $\frac{6 \lambda a^2}{\varepsilon_0}$ $\frac{\sqrt{3} \lambda a}{\varepsilon_0}$ |
$\frac{\sqrt{3} \lambda a}{\varepsilon_0}$ |
The maximum length of the string which can fit into the cube is $\sqrt{3} a$, equal to its body diagonal. The total charge inside the cube is $\sqrt{3} a \lambda$, and hence the total flux through the cube is $\frac{\sqrt{3} a \lambda}{\varepsilon_0}$. ∴ (D) |
