Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Relations and Functions

Question:

The domain of the function $f(x)=\frac{\sqrt{2x-1}+\sqrt{4x+7}}{\sqrt{4-x}+\sqrt{3+17x+1}}$ is:

Options:

\(\begin{bmatrix}-\frac{7}{4},\frac{1}{2}\end{bmatrix}\)

\(\begin{bmatrix}\frac{-3}{17},\frac{1}{2}\end{bmatrix}\)

\(\begin{bmatrix}\frac{-3}{17},4\end{bmatrix}\)

\(\begin{bmatrix}\frac{1}{2},4\end{bmatrix}\)

Correct Answer:

\(\begin{bmatrix}\frac{1}{2},4\end{bmatrix}\)

Explanation:

For domain:-

2x - 1 ≥ 0 ⇒ $x≥\frac{1}{2}$

4x + 7 ≥ 0 ⇒ $x≥\frac{-7}{4}$

4 - x ≥ 0 ⇒ x ≤ 4

4 + 17x ≥ 0 ⇒ $x≥\frac{-4}{17}$

Combining the equations,

$x≥\frac{1}{2}$ & x < 4

$[\frac{1}{2},4]$