If ε0 and μ0 are the electric permittivity and magnetic permeability of free space and ε and μ are the corresponding quantities in the medium, the index of refraction of the medium in terms of above parameter is
Answer & explanation
Correct answer: option 2
Velocity of light in vacuum
$c=\frac{1}{\sqrt{\mu_0ε_0}}$
velocity of light in medium
$v =\frac{1}{\sqrt{\mu ε}}$
$ ∴ \mu = \frac{c}{v}= \left(\frac{\mu ε}{\mu_0 ε_0}\right)^{1/2}$