If (x^2)/yz + (y^2)/zx + (z^2)/xy = 3 Find (x + y + z)3

Given, \(\frac{x^2}{yz}\) + \(\frac{y^2}{zx}\) + \(\frac{z^2}{xy}\) = 3

\(\frac{x^3 + y^3 + z^3}{xyz}\) = 3

x³ + y³ + z³ = 3xyz → (possible only when x +y + z = 0)

(x+ y + z)³ = (0)³ = 0