If \(\frac{x^2}{yz}\) + \(\frac{y^2}{zx}\) + \(\frac{z^2}{xy}\) = 3 Find (x + y + z)3

-2 1 2 0

0

Given, \(\frac{x^2}{yz}\) + \(\frac{y^2}{zx}\) + \(\frac{z^2}{xy}\) = 3 \(\frac{x^3 + y^3 + z^3}{xyz}\) = 3 x3 + y3 + z3 = 3xyz → (possible only when x +y + z = 0) (x+ y + z)3 = (0)3 = 0