Practicing Success
Practicing Success
CUET Preparation Today
| A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is |
0.521 cm 0.525 cm 0.053 cm 0.529 cm |
| 0.529 cm |
| Diameter of the ball = MSR + CSR × (Least count) – Zero error = 5 mm + 25 × 0.001 cm – (–0.004) cm = 0.5 cm + 25 × 0.001 cm – (–0.004) cm = 0.529 cm. |
