In an interference pattern by two identical slits, intensity of central maxima is I. If one slit is closed, intensity of central maxima changes to $I_0$. Then I and $I_0$ are related by
Answer & explanation
Correct answer: option 4
$I_1 = I_2 = a^2$
$I_{max.} = (a+a)^2 = 4a^2 = I$
If one slit is closed,
Intensity, $I_0 = (a)^2$
$∴\frac{I}{I_0}=\frac{4a^2}{a^2}=4$ or $I = 4I_0$