If A and B are any two matrices such that $(A-B)^2=A^2-2 A B+B^2$ then |
$B^2 A^3+A^3 B^2=0$ $A B+B A=0$ $B^3 A^4-A^4 B^3=0$ $A B(B-A)=0$ |
$B^3 A^4-A^4 B^3=0$ |
$(A-B)^2=A^2-A B-BA+B^2 = A^2 - 2AB + B^2$ ⇒ AB = BA .....(1) So $A^2B = ABA$ $A^2 B^2=B A A B$ $A^2 B^2=B A B A$ $A^2 B^2=B^2 A^2$ Similarly $A^3 B^2=B^2 A^3$ $A^3 B^3=B^3 A^3$ $A^4 B^3=B^3 A^4$ ⇒ $B^3 A^4-A^4 B^3=0$ Option C |