Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

Which of the following is true?

Options:

\(\sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\sin^{-1}\frac{24}{85}\)

\(\sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\sin^{-1}\frac{77}{85}\)

\(\sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\sin^{-1}\frac{85}{24}\)

\(\sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\tan^{-1}\frac{36}{77}\)

Correct Answer:

\(\sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\sin^{-1}\frac{77}{85}\)

Explanation:

$sin^{-1}x+sin^{-1}y$

$sin^{-1}(x.\sqrt{1-y^2}+y.\sqrt{1-x^2})$

$=sin^{-1}[\frac{8}{17}.\sqrt{1-\frac{9}{25}}+\frac{3}{5}.\sqrt{1-\frac{64}{289}}]$

$=sin^{-1}[\frac{8}{17}.\frac{4}{5}+\frac{3}{5}.\frac{15}{17}]$

$=sin^{-1}(\frac{77}{85})$