The rate constant of a reaction 2N2O5 → 4NO2 (g) + O2 (g) is 3 x 10-5 s-1. If the rate of reaction is 2.4 x 10-5 mol L-1 s-1, then what is the concentration of N2O5 in mol/L?

1.4 1.2 0.04 0.8

0.8

Rate constant of a reaction, k = 3 x 10-5 s-1  Therefore, it is a first order reaction. r = k [N2O5] 2.4 x 10-5 mol L-1 s-1 = 3 x 10-5 s-1 x [N2O5]  [N2O5] = \(\frac{2.4 × 10^{-5}}{ 3 × 10^{-5}}\) = 0.8 mol/L