Practicing Success
Practicing Success
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In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number) |
$n^{-1}$ n $n^{-2}$ $n^2$ |
$n^2$ |
Bohr radius $r=\frac{\varepsilon_0 n^2 h^2}{\pi Z m e^2} ;~~∴ r \propto n^2$ |
