Three cubes of equal volume are joined end to end. Find the surface area of the resulting cuboid if the diagonal of the cube is $6\sqrt{3}$cm.
Answer & explanation
Correct answer: option 2
We know that,
Diagonal of cube = \(\sqrt {3}\) × Side of cube
= 6\(\sqrt {3}\) = side \(\sqrt {3}\)
Side = 6
So, length of cuboid = 3 × 6 = 18
Breadth = 6
Height= 6
The surface area of the cuboid = 2(lb + bh + lh)
= 2(108 + 36 + 108) = 2 × 252 cm² = 504 cm²