The current in a circuit having constant resistance is tripled. The power dissipation will become:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 9 times
The power dissipated in a resistor is given by Joule heating, \( P = I^{2}R \). For a constant R, \( P\propto I^{2} \).
\( \displaystyle \frac{P'}{P} = \left(\frac{I'}{I}\right)^{2} = 3^{2} = 9 \)