The current in a circuit having constant resistance is tripled. The power dissipation will become: |
6 times 9 times 3/2 times 1/2 times |
9 times |
The correct answer is Option (2) → 9 times In a circuit with constant resistance, the power dissipation (P) - $P=I^2R$ R = Resistance I = Current $I'=3I$ (given) $∴P'=(3I)^2R$ $=9I^2R$ $=9P$ |