2 men and 7 women can complete a work in 28 days, where as 6 men and 16 women can do the same work in 11 days. In how many days will 5 men and 4 women, working together, complete the same work?
Answer & explanation
Correct answer: option 3
Men = M Women = W
(2M + 7W) × 28 = (6M + 16W)11
56M + 196W = 66M + 176W
20W = 10M
2W = 1M (or Efficiency of M : W = 2 : 1)
Now → 2 M + 7 W ⇒ 28 days
↓ x2 (Changing in women)
4 W + 7 W ⇒ 28 days
11 W ⇒ 28 days
Total work = efficiency × time = 11 W × 28 days = 308
We have
⇒ 5M + 4W
↓ x2 (changing in women)
⇒ 10 W + 4 W = 14 W
14W or (5M + 4W) can do it in = \(\frac{308}{14}\) = 22 days