Practicing Success
The value of determinant $\left|\begin{array}{lll}a-b & b-c & c-a \\ b-c & c-a & a-b \\ c-a & a-b & b-c\end{array}\right|$ is : |
$(a-b)(b-c)(c-a)$ $abc$ $a^2+b^2+c^2$ 0 |
0 |
$P = \left|\begin{array}{lll}a-b & b-c & c-a \\ b-c & c-a & a-b \\ c-a & a-b & b-c\end{array}\right|$ so $c_1 \rightarrow c_1+c_2+c_3$ $P=\left|\begin{array}{lll} $=\left|\begin{array}{ccc}0 & b-c & c-a \\ 0 & c-a & a-b \\ 0 & a-b & b-c\end{array}\right|=0$ $P=0$ |