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For a given data of 5 observations $∑y= 311, ∑x^2 = 10$ and $∑xy = 90.$ The equation of the trend line |
$y_t = 62.2+9x$ $y_t = 9+62.2x$ $y_t = 31.1+18x$ $y_t = 18+31.1x$ |
$y_t = 62.2+9x$ |
The correct answer is Option (1) → $y_t = 62.2+9x$ The equation of the trend line is, $y=a+bx$ $=\frac{∑y}{n}+\frac{∑xy}{x^2}x$ $=\frac{311}{5}+\frac{90}{10}x$ $=62.9+9x$ |
