The solution of the inequality $\log_{1/2} \sin^{-1}x>\log_{1/2}\cos^{-1}x$ is:
Answer & explanation
Correct answer: option 4
$\sin^{-1}x<\cos^{-1}x;\sin^{-1}x<\frac{π}{2}-\sin^{-1}x$
$⇒\sin^{-1}x<\frac{π}{4}⇒0<x<\frac{1}{\sqrt{2}}$; Also, $\sin^{-1}x>0$