If A is a 3 × 3 matrix, whose elements are given by $a_{i j}=\frac{1}{3}|-3 i+j|$, then $a_{23}+a_{33}$ is:

3

The correct answer is Option (2) → 3

$a_{ij}=\frac{1}{3}|-3i+j|$

$a_{23}=\frac{1}{3}|-3(2)+3|=\frac{1}{3}|-6+3|=\frac{1}{3}\cdot 3=1$

$a_{33}=\frac{1}{3}|-3(3)+3|=\frac{1}{3}|-9+3|=\frac{1}{3}\cdot 6=2$

$a_{23}+a_{33}=1+2=3$

$a_{23}+a_{33}=3$