ABCD is a kite with $\angle A=46°$ and $\angle C=28°$. Find the measure of $\angle B$.
Answer & explanation
Correct answer: option 2
ABCD is a kite . So, AB = BC and AD = DC
And diagonal AC and BD bisect their respective angles.
∠A = 46º and ∠C = 28º
Diagonal AC bisect angle ∠A and ∠C
So, ∠BAC = 23º and ∠ACB = 14º
In triangle ABC ,
∠BAC + ∠ACB + ∠ABC = 180º
23º + 14º + ∠ABC = 180º
∠ABC = 180º - 37º
= 143º