If θ = 30°, then find sin2θ + 2cosθ.
Answer & explanation
Correct answer: option 3
sin2θ + 2cosθ = sin ( 2× 30)° + 2cos30°
= \(\frac{√3}{2}\) + 2 × \(\frac{√3}{2}\) = 3\(\frac{√3}{2}\)
If θ = 30°, then find sin2θ + 2cosθ.
Correct answer: option 3
sin2θ + 2cosθ = sin ( 2× 30)° + 2cos30°
= \(\frac{√3}{2}\) + 2 × \(\frac{√3}{2}\) = 3\(\frac{√3}{2}\)