CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(II), (B)-(I), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(II), (B)-(I), (C)-(IV), (D)-(III) |
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
(A) Kolbe's Reaction → (II) Salicylic acid: Known as the Kolbe-Schmitt reaction, it involves treating sodium phenoxide (from phenol) with CO₂ under pressure and heat, followed by acidification, to yield salicylic acid (2-hydroxybenzoic acid). (B) Reimer-Tiemann Reaction → (I) Salicylaldehyde: Phenol reacts with chloroform in the presence of a strong base (e.g., NaOH), generating dichlorocarbene, which leads to ortho-formylation and yields salicylaldehyde (2-hydroxybenzaldehyde). (C) Etard Reaction → (IV) Benzaldehyde: Toluene (or other alkylbenzenes) is oxidized using chromyl chloride (CrO₂Cl₂), forming a complex that hydrolyzes to benzaldehyde. (D) Sandmeyer Reaction → (III) Chlorobenzene: Aryl diazonium salts (from anilines) react with CuCl (or similar copper(I) salts) to replace the diazonium group with chlorine, yielding chlorobenzene (or other aryl halides). |
