Match List-I with List-II
|
List-I Name of the Reaction |
List-II Compound synthesized |
|
(A) Kolbe's Reaction |
(I) Salicylaldehyde |
|
(B) Reimer Teimann Reaction |
(II) Salicylic acid |
|
(C) Etard Reaction |
(III) Chlorobenzene |
|
(D) Sandmeyer Reaction |
(IV) Benzaldehyde |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (2) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
|
List-I Name of the Reaction |
List-II Compound synthesized |
|
(A) Kolbe's Reaction |
(II) Salicylic acid |
|
(B) Reimer Teimann Reaction |
(I) Salicylaldehyde |
|
(C) Etard Reaction |
(IV) Benzaldehyde |
|
(D) Sandmeyer Reaction |
(III) Chlorobenzene |
(A) Kolbe's Reaction → (II) Salicylic acid: Known as the Kolbe-Schmitt reaction, it involves treating sodium phenoxide (from phenol) with CO₂ under pressure and heat, followed by acidification, to yield salicylic acid (2-hydroxybenzoic acid).
(B) Reimer-Tiemann Reaction → (I) Salicylaldehyde: Phenol reacts with chloroform in the presence of a strong base (e.g., NaOH), generating dichlorocarbene, which leads to ortho-formylation and yields salicylaldehyde (2-hydroxybenzaldehyde).
(C) Etard Reaction → (IV) Benzaldehyde: Toluene (or other alkylbenzenes) is oxidized using chromyl chloride (CrO₂Cl₂), forming a complex that hydrolyzes to benzaldehyde.
(D) Sandmeyer Reaction → (III) Chlorobenzene: Aryl diazonium salts (from anilines) react with CuCl (or similar copper(I) salts) to replace the diazonium group with chlorine, yielding chlorobenzene (or other aryl halides).